C++11 simple lambda predicate syntax sample

I have done a simple sample how to use a C++11 lambda expression as predicate for a particular algorithm.

	#include <iostream>
	#include <string>
	#include <algorithm>
	int main() {
	std::string s = "xAAAyyByABCxGxZyIxGyyZI";
	std::cout << "Before: '" << s << "'" << std::endl;
	bool (*pred1)(char) = [](char c) { return c == 'x' || c == 'y'; };
	std::replace_if(s.begin(),s.end(),pred1,'*');
	std::cout << "1st tr: '" << s << "'" << std::endl;
	auto pred2 = [](char c) { return c == '*'; };
	std::replace_if(s.begin(),s.end(),pred2,'#');
	std::cout << "2nd tr: '" << s << "'" << std::endl;
	return 0;
	}

view raw PredicateLambda.cpp hosted with ❤ by GitHub

pred1 demonstrates the result type of a lambda expression is a function pointer.
pred2 demonstrates how to shorten the lengthy type declaration.